The String class includes many methods for handling the string. Look at the examples below:
Private Sub Form1_Load(sender As Object, e As EventArgs) Handles MyBase.Load Dim Alphabet As String = "ABCDEFGHIJKLMNOPQRSTUVWXYZ" Me.Text = Alphabet.Length() '26 Me.Text = Alphabet.ToLower 'abcdefghijklmnopqrstuvwxyz Me.Text = Alphabet.Substring(0, 3) 'ABC start=0, length=3 Me.Text = Alphabet.Substring(5, 2) 'FG start=5, length=2 Me.Text = Alphabet.Substring(20) 'UVWXYZ start=20, everything from tht point Me.Text = Alphabet.IndexOf("D") '3 note: A is 0, B is 1, etc. Me.Text = Alphabet.IndexOf("XYZ") '23 XYZ is found begining in position 23 Me.Text = Alphabet.IndexOf("AX") ' -1 AX is not found Me.Text = Alphabet.StartsWith("A") 'True Me.Text = Alphabet.StartsWith("ABC") 'True Me.Text = Alphabet.StartsWith("XYZ") 'False Me.Text = Alphabet.EndsWith("YZ") 'True Me.Text = Alphabet.Replace("ABC", "*") '*DEFGHIJKLMNOPQRSTUVWXYZ Me.Text = Alphabet.Remove(5, 15) 'ABCDEUVWXYZ Me.Text = Alphabet.Contains("DEF") 'True Dim Sentence As String = "A man and a woman manage the store." Me.Text = Sentence.IndexOf("man") '2 Me.Text = Sentence.LastIndexOf("man") '18 (in management) Me.Text = Sentence.Replace("man", "person") 'A person and a woperson personage the store. Dim Words As String() 'an array to hold the words in the sentence Words = Sentence.Split(" ") 'the space is used to split sentence into an array Me.Text = Words(2) 'and Me.Text = Words(Words.Length - 1) 'store. (last word in sentence plus the dot) End Sub 'Form1_Load
Like arrays, the index on Strings begins with 0. The length() of Alphabet is 26, there are 26 letters with A in position 0 and Z in position 25. We can combine these functions in various ways. For example,
Me.Text = Alphabet.Substring(0, 12).Contains("X") 'False
